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JEE Advanced Toppers 2025: Rajit Gupta Claims AIR 1, Saksham Jindal Ranks AIR 2 — Check Out the Top 10 List

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The Indian Institute of Technology (IIT) Kanpur has announced the results for JEE Advanced 2025.

Candidates who appeared for the exam can now check their scores on the official website at jeeadv.ac.in. Stay tuned for live updates on the JEE Advanced Results 2025.

This year, Rajit Gupta secured the top position, with Saksham Jindal finishing in second place. Both toppers scored 332 marks and belong to the IIT Delhi zone.

Here are the top 10 candidates of JEE Advanced 2025:
  1. Rajit Gupta – 332 – IIT Delhi
  2. Saksham Jindal – 332 – IIT Delhi
  3. Majid Mujahid Husain – 330 – IIT Bombay
  4. Parth Mandar Vartak – 327 – IIT Bombay
  5. Ujjwal Kesari – 324 – IIT Delhi
  6. Akshat Kumar Chaurasia – 321 – IIT Kanpur
  7. Sahil Mukesh Deo – 321 – IIT Bombay
  8. Devesh Pankaj Bhaiya – 319 – IIT Delhi
  9. Arnav Singh – 319 – IIT Hyderabad
  10. Vadlamudi Lokesh – 317 – IIT Hyderabad

Notably, the IIT Delhi zone has four candidates in the top 10, IIT Bombay has three, IIT Hyderabad has two, and IIT Kanpur has one.

The JEE Advanced examination took place on May 18, 2025, conducted in two shifts. Paper 1 was held from 9:00 AM to 12:00 PM, followed by Paper 2 from 2:30 PM to 5:30 PM.

The provisional answer key for JEE Advanced 2025 was released on May 25, with candidates given the opportunity to raise objections until May 27, 5 PM.

A total of 180,422 candidates appeared for both Paper 1 and Paper 2, out of which 54,378 candidates qualified. Among the qualifiers, there are 9,404 female candidates and 44,974 male candidates.

The Joint Seat Allocation Authority (JoSAA) will open the registration window for JoSAA Counselling 2025 on Tuesday, June 3, 2025. Candidates who have qualified in the JEE Advanced examination can apply for the counselling process through the official JoSAA website at josaa.nic.in

For more details and updates, candidates are advised to regularly visit the official JEE Advanced 2025 website.